ravitejapandiri wrote:
Machines X and Y work at their respective constant rates. How many more hours does it take machine Y, working alone, to fill a production order of a certain size than it takes machine X, working alone?
(1) Machines X and Y, working together, fill a production order of this size in two-thirds the time that machine X, working alone, does
(2) Machine Y, working alone, fills a production order of this size in twice the time that machine X, working alone, does
Can you explain this one Bunuel plz?
At the end,we are having a definite quantity "X"..Right?So I still feel the answer is D.
Because there is no other value/variable affecting the outcome except for the "X".Please clarify if I am going badly wrong somewhere!
Attachment:
DS-3 (1).jpg
Machine X rate = \(\frac{1}{X}\)
Machine Y rate = \(\frac{1}{Y}\)
Combined rate = \(\frac{X+Y}{XY}\)
Combined time taken = \(\frac{XY }{ X+Y}\)
(1) Tells us that \(\frac{XY }{ X+Y} = \frac{2X}{3}\)
This tells us \(2X = Y\); INSUFFICIENT.
(2) This statement tells us that \(2X = Y\); INSUFFICIENT.
(1&2) Each statement tells us the same information; INSUFFICIENT.
Answer is E.
_________________
Help me get better -- please critique my responses!